What is the directrix-1/8 (y-8)^2+2 ?

The directrix-1/8 (y-8)^2+2 is x=4

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directrix-1/8 (y-8)^2+2

directrix

- \frac{1}{8} (y - 8)^{2} + 2

x = 4

Solution steps

Rewrite

x = - \frac{1}{8} (y - 8)^{2} + 2

in the standard form:

4 (- 2) (x - 2) = (y - 8)^{2}

(h, k) = (2, 8), p = - 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, 8)

x-coordinate

x = 2 - p

x = 2 - (- 2)

Refine

x = 4

2 x^{2} - 10

y^{2} = 4 (- 4) x

(y + 1)^{2} = - 4 (x - 2)

(x - h)^{2} = 4 (- 8) (y - 3)

100 + 6 x^{2} - 8 x