What is the directrix y+3x^2=0 ?

The directrix y+3x^2=0 is y= 1/12

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directrix y+3x^2=0

directrix

y + 3 x^{2} = 0

y = \frac{1}{12}

Solution steps

Rewrite

y + 3 x^{2} = 0

in the standard form:

4 (- \frac{1}{12}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{12})

Refine

y = \frac{1}{12}

y^{2} - 8 x - 8 y + 24 = 0

y = + x^{2} - 4 x - 32

x^{2} + 2 x + 2

y = x^{2} - 2 x - 15

x^{2} - 10000 x - 24000000