What is the directrix 14x^2 ?

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directrix 14x^2

directrix

14 x^{2}

y = - \frac{1}{56}

Solution steps

Rewrite

y = 14 x^{2}

in the standard form:

4 \cdot \frac{1}{56} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{56}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{56}

Refine

y = - \frac{1}{56}

y = \frac{- 4 x ^{2} + 24 x + 161}{25}

x^{2} - 12 x + 35

x = (2 y + 5)^{2}

6 x^{2} - 12 x

y = (x + 1)^{2} + 1