What is the directrix x-4y^2=0 ?

The directrix x-4y^2=0 is x=-1/16

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directrix x-4y^2=0

directrix

x - 4 y^{2} = 0

x = - \frac{1}{16}

Solution steps

Rewrite

x - 4 y^{2} = 0

in the standard form:

4 \cdot \frac{1}{16} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{16}

Refine

x = - \frac{1}{16}

x = (- y - 1) (y + 3)

y = 4 x^{2} - 8 x + 1

y = 24 x - 3 x^{2}

x = - 5 y^{2}

y = (- x - 1) (x + 3)