What is the directrix y=+x^2-2x+5 ?

The directrix y=+x^2-2x+5 is y= 15/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix y=+x^2-2x+5

directrix

y = + x^{2} - 2 x + 5

y = \frac{15}{4}

Solution steps

Rewrite

y = x^{2} - 2 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - 4) = (x - 1)^{2}

(h, k) = (1, 4), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(1, 4)

y-coordinate

y = 4 - p

y = 4 - \frac{1}{4}

Refine

y = \frac{15}{4}

y = 2 x^{2} - 7 x - 3

x^{2} + 5 x - 7

y^{2} - 6 y - 8 x - 23 = 0

t^{2}

4 x - 3 x^{2}