What is the directrix 4x-3x^2 ?

The directrix 4x-3x^2 is y= 17/12

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directrix 4x-3x^2

directrix

4 x - 3 x^{2}

y = \frac{17}{12}

Solution steps

Rewrite

y = 4 x - 3 x^{2}

in the standard form

4 (- \frac{1}{12}) (y - \frac{4}{3}) = (x - \frac{2}{3})^{2}

(h, k) = (\frac{2}{3}, \frac{4}{3}), p = - \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{2}{3}, \frac{4}{3})

y-coordinate

y = \frac{4}{3} - p

y = \frac{4}{3} - (- \frac{1}{12})

Refine

y = \frac{17}{12}

5 x^{2} + 7

(x + 1)^{2} = - 12 (y - 6)

4 x^{2} - 12 x - 2

3 x^{2} + 4 x - 3

y = 600 - 10 x + 0.25 x^{2}