What is the directrix y=600-10x+0.25x^2 ?

The directrix y=600-10x+0.25x^2 is y=499

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directrix y=600-10x+0.25x^2

directrix

y = 600 - 10 x + 0.25 x^{2}

y = 499

Solution steps

Rewrite

y = 600 - 10 x + 0.25 x^{2}

in the standard form

4 \cdot 1 \cdot (y - 500) = (x - 20)^{2}

(h, k) = (20, 500), p = 1

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(20, 500)

y-coordinate

y = 500 - p

y = 500 - 1

Refine

y = 499

11 x^{2} + 13

- 2 (x + 3) = (y - 1)^{2}

2 y^{2} = - 5 x

12 (x - 1) = (y - 3)^{2}

y = \frac{1}{4} x^{2} - \frac{5}{2} x + \frac{13}{4}

What is the directrix y=600-10x+0.25x^2 ?
The directrix y=600-10x+0.25x^2 is y=499