What is the directrix 9x^2+24x+72y+16=0 ?

The directrix 9x^2+24x+72y+16=0 is y=2

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directrix 9x^2+24x+72y+16=0

directrix

9 x^{2} + 24 x + 72 y + 16 = 0

y = 2

Solution steps

Rewrite

9 x^{2} + 24 x + 72 y + 16 = 0

in the standard form

4 (- 2) (y - 0) = (x - (- \frac{4}{3}))^{2}

(h, k) = (- \frac{4}{3}, 0), p = - 2

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- \frac{4}{3}, 0)

y-coordinate

y = 0 - p

y = 0 - (- 2)

Refine

y = 2

y = x^{2} - 10 x + 5

y = x^{2} - 6 x + 9

x^{2} - 2 x + 8 y + 9 = 0

\frac{1}{20} x^{2}

+ t^{2}

What is the directrix 9x^2+24x+72y+16=0 ?
The directrix 9x^2+24x+72y+16=0 is y=2