What is the directrix 1/20 x^2 ?

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directrix 1/20 x^2

directrix

\frac{1}{20} x^{2}

y = - 5

Solution steps

Rewrite

y = \frac{1}{20} x^{2}

in the standard form:

4 \cdot 5 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 5

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 5

Refine

y = - 5

+ t^{2}

y^{2} - 4 x = 0

x^{2} - 6

4 x^{2} + 3 x - 1

x^{2} + a