What is the directrix x^2+12x+38 ?

The directrix x^2+12x+38 is y= 7/4

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directrix x^2+12x+38

directrix

x^{2} + 12 x + 38

y = \frac{7}{4}

Solution steps

Rewrite

y = x^{2} + 12 x + 38

in the standard form

4 \cdot \frac{1}{4} (y - 2) = (x - (- 6))^{2}

(h, k) = (- 6, 2), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 6, 2)

y-coordinate

y = 2 - p

y = 2 - \frac{1}{4}

Refine

y = \frac{7}{4}

x = - 3 y^{2}

- 0.2 t^{2} + 2.4 t + 98.6

x^{2} + 2 x - 8 y + 33 = 0

6 x^{2} - 6 x

(x - \frac{5}{2})^{2} = 7 (y + 3.75)