What is the directrix y^2=-x ?

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directrix y^2=-x

directrix

y^{2} = - x

x = \frac{1}{4}

Solution steps

Rewrite

y^{2} = - x

in the standard form:

4 (- \frac{1}{4}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{1}{4})

Refine

x = \frac{1}{4}

y = (2 x - 1)^{2}

y = - 12 x^{2} - 29 x + 230

y = x^{2} - 5 x 3

y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

x = (y + 1) y