What is 9x^2+16y^2-144=0 ?

The solution to 9x^2+16y^2-144=0 is Ellipse with (h,k)=(0,0),a=4,b=3

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9x^2+16y^2-144=0

9 x^{2} + 16 y^{2} - 144 = 0

(h, k) = (0, 0), a = 4, b = 3

Solution steps

9 x^{2} + 16 y^{2} - 144 = 0

Rewrite

9 x^{2} + 16 y^{2} - 144 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

x^{2} + y^{2} = 49

f (x) = x^{2} - 1

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

y^{2} = 2 x

y^{2} - 3 y - x + 3 = 0

What is 9x^2+16y^2-144=0 ?
The solution to 9x^2+16y^2-144=0 is Ellipse with (h,k)=(0,0),a=4,b=3