What is the directrix y=-10x^2 ?

The directrix y=-10x^2 is y= 1/40

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directrix y=-10x^2

directrix

y = - 10 x^{2}

y = \frac{1}{40}

Solution steps

Rewrite

y = - 10 x^{2}

in the standard form:

4 (- \frac{1}{40}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{40}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{40})

Refine

y = \frac{1}{40}

\frac{1}{8} x^{2} - y = 0

y = - 2 x^{2} - 3

x^{2} - 2 x - 4 y + 17 = 0

x^{2} - 12 y - 6 x + 5 = 0

x^{2} + 4 x - y + 1 = 0