What is the directrix y^2+8x-6y+25=0 ?

The directrix y^2+8x-6y+25=0 is x=0

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directrix y^2+8x-6y+25=0

directrix

y^{2} + 8 x - 6 y + 25 = 0

x = 0

Solution steps

Rewrite

y^{2} + 8 x - 6 y + 25 = 0

in the standard form

4 (- 2) (x - (- 2)) = (y - 3)^{2}

(h, k) = (- 2, 3), p = - 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 2, 3)

x-coordinate

x = - 2 - p

x = - 2 - (- 2)

Refine

x = 0

5 y = - (x - 3)^{2} - 25

x^{2} + 2 x

y = x^{2} - 8 x + 10

y = x^{2} + 12 x + 45

y = (5 x - 8)^{2}