What is the directrix y=x^2-8x+10 ?

The directrix y=x^2-8x+10 is y=-25/4

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directrix y=x^2-8x+10

directrix

y = x^{2} - 8 x + 10

y = - \frac{25}{4}

Solution steps

Rewrite

y = x^{2} - 8 x + 10

in the standard form

4 \cdot \frac{1}{4} (y - (- 6)) = (x - 4)^{2}

(h, k) = (4, - 6), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(4, - 6)

y-coordinate

y = - 6 - p

y = - 6 - \frac{1}{4}

Refine

y = - \frac{25}{4}

y = x^{2} + 12 x + 45

y = (5 x - 8)^{2}

y = 5 x^{2} + 6 x - 7

(x - 1)^{2} = - 6 (y + 4)

7 x^{2} + 70 x + 178