What is the directrix-0.0000848x^2-0.006005x+1.004 ?

The directrix-0.0000848x^2-0.006005x+1.004 is y=2948.11320…

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directrix-0.0000848x^2-0.006005x+1.004

directrix

- 0.0000848 x^{2} - 0.006005 x + 1.004

y = 2948.11320 \dots

Solution steps

Rewrite

y = - 0.0000848 x^{2} - 0.006005 x + 1.004

in the standard form

4 (- 2948.11320 \dots) (y - 0) = (x - (- \frac{0.006005}{0.0001696}))^{2}

(h, k) = (- \frac{0.006005}{0.0001696}, 0), p = - 2948.11320 \dots

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- \frac{0.006005}{0.0001696}, 0)

y-coordinate

y = 0 - p

y = 0 - (- 2948.11320 \dots)

Refine

y = 2948.11320 \dots

y = x^{2} - 3 x - 4

- 2 x^{2} + 4

(x - 2)^{2} = - 4 (y - 2)

x - y^{2} = 0

9 x^{2} - 4

What is the directrix-0.0000848x^2-0.006005x+1.004 ?
The directrix-0.0000848x^2-0.006005x+1.004 is y=2948.11320…