What is the directrix y=(7x-3)^2 ?

The directrix y=(7x-3)^2 is y=-1/196

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directrix y=(7x-3)^2

directrix

y = (7 x - 3)^{2}

y = - \frac{1}{196}

Solution steps

Rewrite

y = (7 x - 3)^{2}

in the standard form:

4 \cdot \frac{1}{196} (y - 0) = (x - \frac{3}{7})^{2}

(h, k) = (\frac{3}{7}, 0), p = \frac{1}{196}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{3}{7}, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{196}

Refine

y = - \frac{1}{196}

+ 6 x^{2} - 54 x + 120

y = 9 x^{2} + 6 x + 1

x^{2} + 4 x + 7

y = 2 x^{2} - 6 x + 4

\frac{( x - 5 ) ( x - 10 )}{50}