What is the directrix 3y^2-4x-6y+23=0 ?

The directrix 3y^2-4x-6y+23=0 is x= 14/3

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directrix 3y^2-4x-6y+23=0

directrix

3 y^{2} - 4 x - 6 y + 23 = 0

x = \frac{14}{3}

Solution steps

Rewrite

3 y^{2} - 4 x - 6 y + 23 = 0

in the standard form

4 \cdot \frac{1}{3} (x - 5) = (y - 1)^{2}

(h, k) = (5, 1), p = \frac{1}{3}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(5, 1)

x-coordinate

x = 5 - p

x = 5 - \frac{1}{3}

Refine

x = \frac{14}{3}

x^{2} + 4 x - 5

x = \frac{- 1}{4} (y + 2)^{2}

x^{2} - x - 56

y^{2} = 4 a x

y^{2} - 2 y - 4 x + 9 = 0

What is the directrix 3y^2-4x-6y+23=0 ?
The directrix 3y^2-4x-6y+23=0 is x= 14/3