What is the directrix-2x^2+4x-2 ?

The directrix-2x^2+4x-2 is y= 1/8

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directrix-2x^2+4x-2

directrix

- 2 x^{2} + 4 x - 2

y = \frac{1}{8}

Solution steps

Rewrite

y = - 2 x^{2} + 4 x - 2

in the standard form

4 (- \frac{1}{8}) (y - 0) = (x - 1)^{2}

(h, k) = (1, 0), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(1, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{8})

Refine

y = \frac{1}{8}

- x^{2} + 150 x - 2000

(x 2 + 1)^{2}

y = (x + 2) (x - 3)

y = + 3 x^{2} + 24 x - 51

y = \frac{1}{2} (x + 3)^{2} - 2