What is the directrix y=+3x^2+24x-51 ?

The directrix y=+3x^2+24x-51 is y=-1189/12

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directrix y=+3x^2+24x-51

directrix

y = + 3 x^{2} + 24 x - 51

y = - \frac{1189}{12}

Solution steps

Rewrite

y = 3 x^{2} + 24 x - 51

in the standard form

4 \cdot \frac{1}{12} (y - (- 99)) = (x - (- 4))^{2}

(h, k) = (- 4, - 99), p = \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 4, - 99)

y-coordinate

y = - 99 - p

y = - 99 - \frac{1}{12}

Refine

y = - \frac{1189}{12}

y = \frac{1}{2} (x + 3)^{2} - 2

x^{2} + 5 x - 14

(x - 2) = 3 (y - 5)^{2}

y = - x^{2} - 4 x - 2

y = x^{2} - 3 x^{2}

What is the directrix y=+3x^2+24x-51 ?
The directrix y=+3x^2+24x-51 is y=-1189/12