What is the axis (x-2)=3(y-5)^2 ?

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axis (x-2)=3(y-5)^2

axis

(x - 2) = 3 (y - 5)^{2}

y = 5

Solution steps

(x - 2) = 3 (y - 5)^{2}

Rewrite

(x - 2) = 3 (y - 5)^{2}

in the standard form:

4 \cdot \frac{1}{12} (x - 2) = (y - 5)^{2}

Therefore parabola properties are:

(h, k) = (2, 5), p = \frac{1}{12}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 5

y = - x^{2} - 4 x - 2

y = x^{2} - 3 x^{2}

y = 4 x^{2}

y = 4 x^{2} - 4 x^{1}

y = x^{2} - 5 x + 6