What is the axis y=(7x-3)^2 ?

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axis y=(7x-3)^2

axis

y = (7 x - 3)^{2}

x = \frac{3}{7}

Solution steps

y = (7 x - 3)^{2}

Rewrite

y = (7 x - 3)^{2}

in the standard form:

4 \cdot \frac{1}{196} (y - 0) = (x - \frac{3}{7})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{7}, 0), p = \frac{1}{196}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{7}

(x - h)^{2} = 4 p (y - k)

y = x^{2} - x - 6

y^{2} - 10 y - 12 x + 37 = 0

y = - 12 x^{2} - 29 x + 230

y = - \frac{63}{16} + \frac{1}{16} x^{2} - \frac{1}{8} x