What is the axis y=x^2-x-6 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=x^2-x-6

axis

y = x^{2} - x - 6

x = \frac{1}{2}

Solution steps

y = x^{2} - x - 6

Rewrite

y = x^{2} - x - 6

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{25}{4})) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, - \frac{25}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{1}{2}

y^{2} - 10 y - 12 x + 37 = 0

y = - 12 x^{2} - 29 x + 230

y = - \frac{63}{16} + \frac{1}{16} x^{2} - \frac{1}{8} x

y = x^{2} + 8 x - 5

y = 3 x^{2} - 5 x 7