What is the axis y=x^2+8x-5 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=x^2+8x-5

axis

y = x^{2} + 8 x - 5

x = - 4

Solution steps

y = x^{2} + 8 x - 5

Rewrite

y = x^{2} + 8 x - 5

in the standard form

4 \cdot \frac{1}{4} (y - (- 21)) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 21), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 4

y = 3 x^{2} - 5 x 7

y = 7 x^{2} - 10 x + 5

y = - \frac{1}{2} x^{2} - 4 x + 10

y = x^{2} - x - 20

x^{2} + y = 5