What is the axis x^2+y=5 ?

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axis x^2+y=5

axis

x^{2} + y = 5

x = 0

Solution steps

x^{2} + y = 5

Rewrite

x^{2} + y = 5

in the standard form:

4 (- \frac{1}{4}) (y - 5) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 5), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = x^{2} + 2 x - 1 - (2 x^{2} - 3 x + 6)

y = 1 - x^{2}

y = 2 x^{2} - 1 - (5 x - 6)

y = 2 (x + 1)^{2}

y = a x^{2}