What is the axis y=3x-3x^2 ?

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axis y=3x-3x^2

axis

y = 3 x - 3 x^{2}

x = \frac{1}{2}

Solution steps

y = 3 x - 3 x^{2}

Rewrite

y = 3 x - 3 x^{2}

in the standard form

4 (- \frac{1}{12}) (y - \frac{3}{4}) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, \frac{3}{4}), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{1}{2}

y = + (x - 3)^{2} + 24

y = - x^{2} + 5 x - 2

y = x^{2} - 4

y = x^{2} - 20 x + 100

y = x^{2} - 14 x + 48