What is the axis y=x^2-4 ?

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axis y=x^2-4

axis

y = x^{2} - 4

x = 0

Solution steps

y = x^{2} - 4

Rewrite

y = x^{2} - 4

in the standard form:

4 \cdot \frac{1}{4} (y - (- 4)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 4), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = x^{2} - 20 x + 100

y = x^{2} - 14 x + 48

y = (2 x + 5)^{2}

y = - 1.25 x^{2} + 50 x + 4000

y = x^{2} - 5 x - 6