What is the axis y=(2x+5)^2 ?

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axis y=(2x+5)^2

axis

y = (2 x + 5)^{2}

x = - \frac{5}{2}

Solution steps

y = (2 x + 5)^{2}

Rewrite

y = (2 x + 5)^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{2}, 0), p = \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{5}{2}

y = - 1.25 x^{2} + 50 x + 4000

y = x^{2} - 5 x - 6

y = 2 x^{2} + 5 x + 2

y = - 3 x^{2} - 12 x - 9

y = x^{2} - 10 x + 24