What is the axis y=x^2-5x-14 ?

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axis y=x^2-5x-14

axis

y = x^{2} - 5 x - 14

x = \frac{5}{2}

Solution steps

y = x^{2} - 5 x - 14

Rewrite

y = x^{2} - 5 x - 14

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{81}{4})) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, - \frac{81}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{2}

y = 8 x^{2} + 12 x + 3

y = 4 x^{2} - 8 x + 7

x^{2} = - 6 y

+ 5 x^{2} + 30 x + 24 y = 51

x^{2} = - 4 y