What is the axis x^2=-6y ?

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axis x^2=-6y

axis

x^{2} = - 6 y

x = 0

Solution steps

x^{2} = - 6 y

Rewrite

x^{2} = - 6 y

in the standard form:

4 (- \frac{3}{2}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{3}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

+ 5 x^{2} + 30 x + 24 y = 51

x^{2} = - 4 y

y = - 5 x^{2} + 118 x + 7

y = \frac{6 x}{7} \cdot \frac{4 x}{3}

x = - 3 y^{2} + 5