What is the axis y=-5x^2+118x+7 ?

The axis y=-5x^2+118x+7 is x= 59/5

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axis y=-5x^2+118x+7

axis

y = - 5 x^{2} + 118 x + 7

x = \frac{59}{5}

Solution steps

y = - 5 x^{2} + 118 x + 7

Rewrite

y = - 5 x^{2} + 118 x + 7

in the standard form

4 (- \frac{1}{20}) (y - \frac{3516}{5}) = (x - \frac{59}{5})^{2}

Therefore parabola properties are:

(h, k) = (\frac{59}{5}, \frac{3516}{5}), p = - \frac{1}{20}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{59}{5}

y = \frac{6 x}{7} \cdot \frac{4 x}{3}

x = - 3 y^{2} + 5

y = - x^{2} + 5 x - 7

y = x^{2} - 2 x - 3

y = - x^{2} - 6 x - 8