What is the axis y=-x^2-6x-8 ?

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axis y=-x^2-6x-8

axis

y = - x^{2} - 6 x - 8

x = - 3

Solution steps

y = - x^{2} - 6 x - 8

Rewrite

y = - x^{2} - 6 x - 8

in the standard form

4 (- \frac{1}{4}) (y - 1) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 1), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 3

y = 3 x^{2} - 5 x + 7

y^{2} = - 28 x

y = 6 x^{2} - 7 x - 3

y = x^{2} - x + 5

y = x^{2} - 12 x + 46