What is the axis y=3x^2-5x+7 ?

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axis y=3x^2-5x+7

axis

y = 3 x^{2} - 5 x + 7

x = \frac{5}{6}

Solution steps

y = 3 x^{2} - 5 x + 7

Rewrite

y = 3 x^{2} - 5 x + 7

in the standard form

4 \cdot \frac{1}{12} (y - \frac{59}{12}) = (x - \frac{5}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{6}, \frac{59}{12}), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{6}

y^{2} = - 28 x

y = 6 x^{2} - 7 x - 3

y = x^{2} - x + 5

y = x^{2} - 12 x + 46

18 x^{2} - 64 x - 14 y + 150 = 0