What is the axis y=-((x+3)^2)/(20)+1 ?

The axis y=-((x+3)^2)/(20)+1 is x=-3

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axis y=-((x+3)^2)/(20)+1

axis

y = - \frac{( x + 3 ) ^{2}}{20} + 1

x = - 3

Solution steps

y = - \frac{( x + 3 ) ^{2}}{20} + 1

Rewrite

y = - \frac{( x + 3 ) ^{2}}{20} + 1

in the standard form:

4 (- 5) (y - 1) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 1), p = - 5

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 3

F = \frac{m v ^{2}}{r}

y^{2} = x - 3

y = 4 (x + 1)^{2} - 3

y = x^{2} + 8 x + 12

x^{2} + 8 y + 2 x - 23 = 0