What is the axis x^2+6y=0 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis x^2+6y=0

axis

x^{2} + 6 y = 0

x = 0

Solution steps

x^{2} + 6 y = 0

Rewrite

x^{2} + 6 y = 0

in the standard form:

4 (- \frac{3}{2}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{3}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

x^{2} - 2 x + 8 y + 9 = 0

y^{2} = - 8 x

y = 3 x^{2} - 12 x + 8

x^{2} = 8 y

y = x^{2} + 4 x - 45