What is the axis y=(2X+5)(3X-7) ?

The axis y=(2X+5)(3X-7) is X=-1/12

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axis y=(2X+5)(3X-7)

axis

y = (2 X + 5) (3 X - 7)

X = - \frac{1}{12}

Solution steps

y = (2 X + 5) (3 X - 7)

Rewrite

y = (2 X + 5) (3 X - 7)

in the standard form

4 \cdot \frac{1}{24} (y - (- \frac{841}{24})) = (X - (- \frac{1}{12}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{841}{24}, - \frac{1}{12}), p = \frac{1}{24}

Parabola is of the form

4 p (y - h) = (X - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

X = - \frac{1}{12}

f (x) = - x^{2} - 4 x + 5

x = y^{2} - 2 y

x = + (y + 3)^{2}

y = x^{2} - 2 x^{1}

y = x^{2} - 2 x^{2}