What is the axis x=+(y+3)^2 ?

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axis x=+(y+3)^2

axis

x = + (y + 3)^{2}

y = - 3

Solution steps

x = (y + 3)^{2}

Rewrite

x = (y + 3)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (0, - 3), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 3

y = x^{2} - 2 x^{1}

y = x^{2} - 2 x^{2}

y = 12 x^{2} - 72 x + 77

y = (x - 4)^{2}

y = + 4 - x^{2}