What is the axis y=12x^2-72x+77 ?

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axis y=12x^2-72x+77

axis

y = 12 x^{2} - 72 x + 77

x = 3

Solution steps

y = 12 x^{2} - 72 x + 77

Rewrite

y = 12 x^{2} - 72 x + 77

in the standard form

4 \cdot \frac{1}{48} (y - (- 31)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 31), p = \frac{1}{48}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = (x - 4)^{2}

y = + 4 - x^{2}

y^{2} = 12 x

y = 3 x^{2} 4

y = x^{2} - 4 x - 12