What is the axis y=(x-4)^2 ?

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axis y=(x-4)^2

axis

y = (x - 4)^{2}

x = 4

Solution steps

y = (x - 4)^{2}

Rewrite

y = (x - 4)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 0), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 4

y = + 4 - x^{2}

y^{2} = 12 x

y = 3 x^{2} 4

y = x^{2} - 4 x - 12

4 y^{2} - 48 x - 20 y = 71