What is the axis 4y^2-48x-20y=71 ?

The axis 4y^2-48x-20y=71 is y= 5/2

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axis 4y^2-48x-20y=71

axis

4 y^{2} - 48 x - 20 y = 71

y = \frac{5}{2}

Solution steps

4 y^{2} - 48 x - 20 y = 71

Rewrite

4 y^{2} - 48 x - 20 y = 71

in the standard form

4 \cdot 3 (x - (- 2)) = (y - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (- 2, \frac{5}{2}), p = 3

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = \frac{5}{2}

x = - 5 y^{2}

y = - 3 x^{2} + 12 x - 8

(x - 3)^{2} = 8 (y - 5)

y = \frac{x ^{2} 5 x 8}{x 3}

x^{2} - 4 y = 0