What is the axis (x-3)^2=8(y-5) ?

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axis (x-3)^2=8(y-5)

axis

(x - 3)^{2} = 8 (y - 5)

x = 3

Solution steps

(x - 3)^{2} = 8 (y - 5)

Rewrite

(x - 3)^{2} = 8 (y - 5)

in the standard form:

4 \cdot 2 (y - 5) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 5), p = 2

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = \frac{x ^{2} 5 x 8}{x 3}

x^{2} - 4 y = 0

y = - 2 x^{2} - 12 x - 10

y^{2} = - x

y = - 3 x^{2}