What is the axis 3x^2+8y=0 ?

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axis 3x^2+8y=0

axis

3 x^{2} + 8 y = 0

x = 0

Solution steps

3 x^{2} + 8 y = 0

Rewrite

3 x^{2} + 8 y = 0

in the standard form:

4 (- \frac{2}{3}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{2}{3}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 3 x^{2} + 9 x + 9

y = 0.07 x^{2} + 20 x + 350

y = (x - 9)^{2} - 2

y^{2} - 8 x - 16 = 0

(x + 7)^{2} = 5 (y + 3)