What is the axis y=x^2-12x+35 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=x^2-12x+35

axis

y = x^{2} - 12 x + 35

x = 6

Solution steps

y = x^{2} - 12 x + 35

Rewrite

y = x^{2} - 12 x + 35

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - 1), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 6

(x + 1)^{2} = (y + 4)

y = (2 x + 1)^{2}

y = 12 x^{2}

y^{2} = 28 x

y = 0.00225 x^{2} + 5999.9325 x + 0.50625