What is the axis y=7x^2-9x-5 ?

The axis y=7x^2-9x-5 is x= 9/14

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axis y=7x^2-9x-5

axis

y = 7 x^{2} - 9 x - 5

x = \frac{9}{14}

Solution steps

y = 7 x^{2} - 9 x - 5

Rewrite

y = 7 x^{2} - 9 x - 5

in the standard form

4 \cdot \frac{1}{28} (y - (- \frac{221}{28})) = (x - \frac{9}{14})^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{14}, - \frac{221}{28}), p = \frac{1}{28}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{9}{14}

y = x^{2} - 6 x + 10

y = - 0.23 x^{2} + 1.87 x + 1.5

y = - 3 x^{2} - 42 x - 22

x^{2} = 12 y

y = 4 x^{2} - 2 x