What is the axis y^2-4x=0 ?

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axis y^2-4x=0

axis

y^{2} - 4 x = 0

y = 0

Solution steps

y^{2} - 4 x = 0

Rewrite

y^{2} - 4 x = 0

in the standard form:

4 \cdot 1 \cdot (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

x^{2} - y = 0

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

y - 2 = 3 (x - 5)^{2}

y = 160 x - 16 x^{2}

x^{2} + 6 x + 3 y + 2 = 0