What is the vertices (x^2)/9-(y^2)/4 =1 ?

The vertices (x^2)/9-(y^2)/4 =1 is (3,0),(-3,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (x^2)/9-(y^2)/4 =1

vertices

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1

(3, 0), (- 3, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 2

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

y^{2} - 4 y + 4 x = - 16

x^{2} + y^{2} + 6 x - 4 y - 23 = 0

y^{2} = - 8 x

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137

4 x^{2} + 4 y^{2} - 4 x + 2 y - 1 = 0

What is the vertices (x^2)/9-(y^2)/4 =1 ?
The vertices (x^2)/9-(y^2)/4 =1 is (3,0),(-3,0)