What is the axis y=8-2x^2 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=8-2x^2

axis

y = 8 - 2 x^{2}

x = 0

Solution steps

y = 8 - 2 x^{2}

Rewrite

y = 8 - 2 x^{2}

in the standard form:

4 (- \frac{1}{8}) (y - 8) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 8), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = - x^{2} + 6 x + 2

y = (x - 3) (x - 7)

- 2 x^{2} + 24 x + y - 70 = 0

+ y^{2} = 4 x

y = (x + 2) (x - 3)