What is the axis y=(x-3)(x-7) ?

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axis y=(x-3)(x-7)

axis

y = (x - 3) (x - 7)

x = 5

Solution steps

y = (x - 3) (x - 7)

Rewrite

y = (x - 3) (x - 7)

in the standard form

4 \cdot \frac{1}{4} (y - (- 4)) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, - 4), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 5

- 2 x^{2} + 24 x + y - 70 = 0

+ y^{2} = 4 x

y = (x + 2) (x - 3)

x = (- y - 1) (y + 3)

y = 2 (x - 1)^{2}