What is the axis x=(y+4)^2 ?

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axis x=(y+4)^2

axis

x = (y + 4)^{2}

y = - 4

Solution steps

x = (y + 4)^{2}

Rewrite

x = (y + 4)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (0, - 4), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 4

y = + x^{2} - 9

y = + \frac{9 x ^{2} - 6 x + 3}{3} x

x^{2} - 12 x + 16 y + 68 = 0

y = 2 x^{2} - 4 x

y = 4 - (x - 1)^{2}