What is the axis y=x^2+2x+3 ?

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axis y=x^2+2x+3

axis

y = x^{2} + 2 x + 3

x = - 1

Solution steps

y = x^{2} + 2 x + 3

Rewrite

y = x^{2} + 2 x + 3

in the standard form

4 \cdot \frac{1}{4} (y - 2) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, 2), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = 3.1 + 6.6 x - 2.3 x^{2}

y = 2 x^{2} + 4 x - 3

y = 2 x^{2} + 4 x - 6

y = (\frac{1}{2} x + 4)^{2}

y = 2 x^{2} - 8